stegouuid alternatives and similar packages
Based on the "Cryptography" category.
Alternatively, view stegouuid alternatives based on common mentions on social networks and blogs.

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README
stegouuid
A generator and verifier for steganographic numbers that look random
The standard use of this package is to generate a 64bit number and use this, along with a secret key, as input to the marking function.
Example:
secretHi = KeyHi64 12345  secret key hi 64 bits
secretLo = KeyLo64 67890  secret key low 64 bits
main :: IO ()
main = do
putStrLn "Is this marked?"
r < randomIO :: IO Word64  get 64bit random number
let x = mark secretHi secretLo r  produce marked 128bit UUID
print x
print (isMarked secretHi secretLo x)  True
Security considerations
This is a poor man's MAC. We use SHA256 to generate the second half of the UUID from the 64bit random looking input and the secret key. The small number of bits limits the security.
We will start getting collisions on the 64bit random number after about 2^{32} numbers are used. But this just means we will be providing the function with the same input, so the same output will be produced.
False Negatives
This is zero. If you produced the number with the mark
function, this number will always be
detected with isMarked
as long as you provide the correct key.
False positives
This is false detection. We worry about a UUID that was not generated using mark
but is
detected as marked by isMarked
. (A malicious adversary can always replay any UUIDs known as
marked. Thus, we will consider only new UUIDs.)
Assuming SHA256 is a perfect pseudorandom function, its truncated output, i.e. the last 64 bits of the UUID, does not leak any information about the secret key. Given a fixed secret key, for any 64bit input (corresponding to the the first half of the UUID), there is a unique 64bit output (corresponding to the second half of the UUID). There is only one such output per 64bit input. So, the probability of finding such input from a random draw is 2^{64}. The adversary would have more than a 1/2 chance of finding it after 2^{63} guesses.
Information leakage
The adversary can only know a UUID is marked if it is able to differentiate the output of truncated SHA256 from a pseudorandom function. I am unaware of any significant results in doing so. The key is 128bits in length, so going through all possible values is currently unfeasible.